Complex Queries in SQL

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These questions are the most frequently asked in interviews.

1. To fetch ALTERNATE records from a table. (EVEN NUMBERED)select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);
2. To select ALTERNATE records from a table. (ODD NUMBERED)select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);
3. Find the 3rd MAX salary in the emp table.select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);
4. Find the 3rd MIN salary in the emp table.select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);
5. Select FIRST n records from a table.select * from emp where rownum <= &n;
6. Select LAST n records from a tableselect * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);
7. List dept no., Dept name for all the departments in which there are no employees in the department.select * from dept where deptno not in (select deptno from emp);  
   alternate solution:  select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);
   altertnate solution:  select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;
8. How to get 3 Max salaries ?select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;
9. How to get 3 Min salaries ?select distinct sal from emp a  where 3 >= (select count(distinct sal) from emp b  where a.sal >= b.sal);
10. How to get nth max salaries ?
    select distinct hiredate from emp a where &n =  (select count(distinct sal) from emp b where a.sal >= b.sal);
11. Select DISTINCT RECORDS from emp table.select * from emp a where  rowid = (select max(rowid) from emp b where  a.empno=b.empno);
12. How to delete duplicate rows in a table?delete from emp a where rowid != (select max(rowid) from emp b where  a.empno=b.empno);
13. Count of number of employees in  department  wise.select count(EMPNO), b.deptno, dname from emp a, dept b  where a.deptno(+)=b.deptno  group by b.deptno,dname;
14.  Suppose there is annual salary information provided by emp table. How to fetch monthly salary of each and every employee?
    select ename,sal/12 as monthlysal from emp;
15. Select all record from emp table where deptno =10 or 40.
    select * from emp where deptno=30 or deptno=10;
16. Select all record from emp table where deptno=30 and sal>1500.
    select * from emp where deptno=30 and sal>1500;
17. Select  all record  from emp where job not in SALESMAN  or CLERK.
    select * from emp where job not in ('SALESMAN','CLERK');
18. Select all record from emp where ename in 'BLAKE','SCOTT','KING'and'FORD'.
    select * from emp where ename in('JONES','BLAKE','SCOTT','KING','FORD');
19. Select all records where ename starts with ‘S’ and its lenth is 6 char.
    select * from emp where ename like'S____';
20. Select all records where ename may be any no of  character but it should end with ‘R’.
    select * from emp where ename like'%R';
21. Count  MGR and their salary in emp table.
    select count(MGR),count(sal) from emp;
22. In emp table add comm+sal as total sal  .
    select ename,(sal+nvl(comm,0)) as totalsal from emp;
23. Select  any salary <3000 from emp table. 
    select * from emp  where sal> any(select sal from emp where sal<3000);
24. Select  all salary <3000 from emp table. 
    select * from emp  where sal> all(select sal from emp where sal<3000);
25. Select all the employee  group by deptno and sal in descending order.
    select ename,deptno,sal from emp order by deptno,sal desc;
26. How can I create an empty table emp1 with same structure as emp?
    Create table emp1 as select * from emp where 1=2;
27. How to retrive record where sal between 1000 to 2000?
    Select * from emp where sal>=1000 And  sal<2000
28. Select all records where dept no of both emp and dept table matches.
    select * from emp where exists(select * from dept where emp.deptno=dept.deptno)
29. If there are two tables emp1 and emp2, and both have common record. How can I fetch all the recods but common records only once?
    (Select * from emp) Union (Select * from emp1)
30. How to fetch only common records from two tables emp and emp1?
    (Select * from emp) Intersect (Select * from emp1)
31.  How can I retrive all records of emp1 those should not present in emp2?
    (Select * from emp) Minus (Select * from emp1)
32. Count the totalsa  deptno wise where more than 2 employees exist.
    SELECT  deptno, sum(sal) As totalsal
    FROM emp
    GROUP BY deptno
    HAVING COUNT(empno) > 2

                                                                                                                                                 Previous......

Continue Statement in C#

The continue statement in C# works somewhat like the break statement. Instead of forcing termination, however, continue forces the next iteration of the loop to take place, skipping any code in between.

For the for loop, continue statement causes the conditional test and increment portions of the loop to execute. For the while and do...while loops, continue statement causes the program control passes to the conditional tests.

Syntax:

The syntax for a continue statement in C# is as follows:

continue;

Flow Diagram:

Example:

using System;
 
namespace Continue_Statement
{
  class Program
   {
     static void Main(string[] args)
      {
        int i = 0; 
        while(i<10)
         {
           i++;
           if (i < 6)
            {
              continue;
            }    
           Console.WriteLine(i);
         }           
        Console.Read();
      }
   }
}

When the above code is compiled and executed, it produces the following result:

O/P :6 7 8 9 10
 

Break statement in C#

The break statement in C# has following two usage:

1. When the break statement is encountered inside a loop, the loop is immediately terminated and program control resumes at the next statement following the loop.
2. It can be used to terminate a case in the switch statement.

If you are using nested loops (i.e., one loop inside another loop), the break statement will stop the execution of the innermost loop and start executing the next line of code after the block.

Syntax:

The syntax for a break statement in C# is as follows:

break;

Flow Diagram:

Example:

using System;
 


namespace break_statement

{
 

class Program

{

static void Main(string[] args)
      

{
        

int i = 0;
 
        

while (i < 100)
         

{
           

Console.WriteLine(i);
           

if (i == 20)
            

{
              

Console.WriteLine("breaking the current segment...");
              break;
            

}
           

i++;
         

}  
        

Console.ReadLine();
     

 }
  

 }


}

When the above code is compiled and executed, it produces the following result:

0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
breaking the current segment

Nested Loop in C#

C# allows to use one loop inside another loop. Following section shows few examples to illustrate the concept.

Syntax:

The syntax for a nested for loop statement in C# is as follows:

for ( init; condition; increment )
{
   for ( init; condition; increment )
   {
      statement(s);
   }
   statement(s);
}

The syntax for a nested while loop statement in C# is as follows:

while(condition)
{
   while(condition)
   {
      statement(s);
   }
   statement(s);
}

The syntax for a nested do...while loop statement in C# is as follows:

do
{
   statement(s);
   do
   {
      statement(s);
   }while( condition );

}while( condition );

A final note on loop nesting is that you can put any type of loop inside of any other type of loop. For example a for loop can be inside a while loop or vice versa.

Example:

The following program uses a nested for loop to find the prime numbers from 2 to 100:

using System;

namespace Loops
{
    
   class Program
   {
      static void Main(string[] args)
      {
         /* local variable definition */
         int i, j;

         for (i = 2; i < 100; i++)
         {
            for (j = 2; j <= (i / j); j++)
               if ((i % j) == 0) break; // if factor found, not prime
            if (j > (i / j)) 
               Console.WriteLine("{0} is prime", i);
         }

         Console.ReadLine();
      }
   }
} 

When the above code is compiled and executed, it produces the following result:

2 is prime
3 is prime
5 is prime
7 is prime
11 is prime
13 is prime
17 is prime
19 is prime
23 is prime
29 is prime
31 is prime
37 is prime
41 is prime
43 is prime
47 is prime
53 is prime
59 is prime
61 is prime
67 is prime
71 is prime
73 is prime
79 is prime
83 is prime
89 is prime
97 is prime